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s^2-30s+11=0
a = 1; b = -30; c = +11;
Δ = b2-4ac
Δ = -302-4·1·11
Δ = 856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{856}=\sqrt{4*214}=\sqrt{4}*\sqrt{214}=2\sqrt{214}$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{214}}{2*1}=\frac{30-2\sqrt{214}}{2} $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{214}}{2*1}=\frac{30+2\sqrt{214}}{2} $
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